To determine the nature of the bonds, we must first find the electronegativity level of each atom of the bond, and find the difference, and then use the below chart to determine if its nature is covalent or ionic and adding the prefixes to emphasize its nature in a more accurate way. Remember that double bonds do not influence the electonegativity values or difference, and that 0 is an absolutely covalent bond.
Now to get started with determining natures of the bonds!
C-H: 3.5-2.2 is equal to a difference of 0.3, therefore this single bond between one carbon atom and one hydrogen atom is a very covalent polar bond.
C=C: 2.5-2.5 is equal to a difference of 0.0, therefore this double bond between two carbon atoms is an absolutely covalent bond.
C-C: 2.5-2.5 is equal to a difference of 0.0, therefore this single bond between two carbon atoms is an absolutely covalent bond.
O-C: 3.5-2.5 is equal to a difference of 1.0, therefore this single bond between one oxygen atom and one carbon atom is a moderately covalent polar bond.
O=C: 3.5-2.5 is equal to a difference of 1.0, therefore this double bond between one oxygen atom and one carbon atom is a moderately covalent polar bond.
O-H: 3.5-2.2 is equal to a difference of 1.3, therefore this single bond between one oxygen atom and one hydrogen atom is a slightly polar covalent bond.
Very organized, with an accurate showing of both the polarity and the intermolecular forces, the design is simple, but it brings out the rest of the blog, especially the ad. Very convincing, and great use of pictures. Easy to understand, all around great job!
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